"""
Goal/purpose: This is a debugging exercise to be solved in class. 

This program attempts to calculate the sums of the cube roots 
of the integers from 1 to 1,000,000. The correct answer is 75000049.7226595

There are three things wrong with the program.

I am leaving out most of the comments that I would normally include becuse I 
want to make it less obvious what I've done wrong.

Please correct these issues.

Author: George Gollin

File: unit02_in_class_warmup.py 

Date: June 7, 2017

Physics 298 owl, University of Illinois at Urbana-Champaign

"""

###################################
# Import libraries 
###################################

# no libraries are needed

###################################
# Define and initialize variables
###################################

# the correct value is...

correct_value = 75000049.7226595

# Accumulator variable for a sum

accumulator_variable = 0

# upper limit variable for the loop 

last_term = 1000000

###############################################################################
# Loop doing the work. Normally this would be much more thoroughly commented.
###############################################################################

for index in range (1, last_term):

    increment_variable = index ** 1/3
    accumulator_variable = accumulator_variable + increment_variable  

###############################################################################
# End of loop. Print the results.
###############################################################################

    print("all done. Result is... ", accumulator_variable)

print("my value minus the correct value is ", \
accumulator_variable - correct_value)

###############################################################################
# Make informative comments on the results you just found, like how quickly
# the series converges, and its comparison to the true value of pi.
###############################################################################

print("well, that was fun and I am easily amused.")