This exam consists of 29 questions; true-false questions are worth 2
points each, three-choice multiple choice questions are worth 3 points
each, five-choice multiple choice questions are worth 6 points each.
The maximum possible score is 91. The exam period was 90 minutes; the
mean was 75.9; the median was 78. Click here to see
of the formula sheet that came with the exam.
A person is nearsighted (myopic) and without glasses the furthest
distance that she can see an object clearly is 66.4 cm.
You would prescribe contact lenses with
(a) negative focal length.
(b) positive focal length.
(a) |P| = 1.47 diopters
(b) |P| = 1.51 diopters
(c) |P| = 1.55 diopters
(b) only when the object is between the focal point and the mirror.
(a) 15 cm
(b) 20 cm
(c) 25 cm
A light beam enters a plastic slab (n = 1.6, d = 10 cm) with an incident
angle 30o, at point A and exits at point B (see
Calculate the horizontal distance x the beam travels in going
from A to B?
(a) x = 3.3 cm
(b) x = 4.4 cm
(c) x = 5.7 cm
(a) t = 0.33 ns
(b) t = 0.44 ns
(c) t = 0.56 ns
An object is located between the focal point f and twice f at the
left of a converging lens made from glass (n = 1.5), as shown in
The image is located
(a) between the lens and C.
(b) between C and D.
(c) to the right of D.
(a) closer to the lens.
(b) farther from the lens.
(c) in the same position as before.
In the figure is shown a two-lens system. Lens #1 is a converging
lens with f1 = 15 cm, while Lens #2 is a diverging lens with
f1 = -10 cm. They are placed 7 cm apart. An object of height
5 cm is placed 40 cm to the left of lens #1.
The image produced by ONLY the Lens #1 is a distance di1
(a) di1 = -24 cm (to the left of lens 1)
(b) di1 = -18 cm (to the left of lens 1)
(c) di1 = -12 cm (to the left of lens 1)
(d) di1 = +12 cm (to the right of lens 1)
(e) di1 = +24 cm (to the right of lens 1)
(a) |hi1| = 3 cm
(b) |hi1| = 5 cm
(c) |hi1| = 8 cm
(a) di2 = –24.3 cm (to the left of lens 2)
(b) di2 = –20.1 cm (to the left of lens 2)
(c) di2 = –17.8 cm (to the left of lens 2)
(d) di2 = +17.8 cm (to the right of lens 2)
(e) di2 = +20.1 cm (to the right of lens 2)
(a) |hi2| = 1.8 cm
(b) |hi2| = 2.7 cm
(c) |hi2| = 4.3 cm
Monochromatic light hits a barrier with two slits separated by
distance d = 0.2 mm. The two slits act as two point-like sources of light.
When the light hits a screen a distance L=4m away, the second dark
fringe is y=1.6 cm from the center of the screen. Assume that the two
slits are sufficiently narrow so that you can ignore their widths.
What is the wavelength of the light?
(a) 488 nm
(b) 514 nm
(c) 532 nm
(a) 2.1 cm
(b) 1.6 cm
(c) 1.2 cm
(c) It does not move.
A thin (640 nm) layer of water (n = 1.33) rests on a glass surface (n
= 1.5). Light with wavelength (in air) of 568 nm is incident from
Light reflecting off of the top and bottom layers of the water will interfere
(a) 95 nm
(b) 107 nm
(c) 189 nm
(d) 213 nm
(e) 320 nm
(a) The light of 568 nm will be constructively interfered upon reflections of the film.
(b) The light of 568 nm will be destructively interfered upon reflections of the film.
(c) The interference of 568 nm upon reflections will be neither constructive nor destructive.
Light of 488 nm wavelength is incident on a grating made with 8000
lines/cm. The distance between the grating and the screen is 25 cm.
What distance above the center of the screen will the first bright
(a) 4.8 cm
(b) 7.2 cm
(c) 10.6 cm
(a) 4.2 km
(b) 5.1 km
(c) 5.8 km
A person needs a bifocal lens in order to read books at 30 cm
distance away from the eyes and also to see objects far away. The near
point of the person’s eye is 0.5m. (Typically, a bifocal lens
allows people to read books using the bottom part of the lens.)
Which one of the following pictures best represent a bifocal lens?
(a) 69 cm
(b) 99 cm
(c) 108 cm
(a) 75 cm
(b) 100 cm
(c) 125 cm