This exam consists of 30 questions; true-false questions
are worth 2 points each, three-choice multiple choice questions are
worth 3 points each, five-choice multiple choice questions are worth 6
points each. The maximum possible score is 120. When the
exam was given, the minimum "A" score was 107; the minimum "B" was
92; the minimum "C" was 78; the minimum "D" was 60. The mean was
93.3; the median was 94. Click here to see formula sheet 1, formula sheet 2 that came with the exam.
(a) Eza = Ezb = Ezc
(b) Eza = - Ezc ; Ezb = 0
(c) Eza > Ezb > Ezc
(a) not flow.
(b) flow in the same direction as in the left ring.
(c) flow in the opposite direction as in the left ring.
(a) L, N and I are doubled.
(b) L and I are doubled and N is intact.
(c) N and I are doubled and L is intact.
The Acme Particle Spectrometer shown here consists of a uniform
magnetic field |B| = 0.93 T either into or out of the page, in
the region of the shaded box. Particles #1 through #4 all have charge
magnitude |q| = 1.6 × 10-19 C. They enter with
the same initial velocity v = 2 ×
106 m/s and follow the trajectories shown.
Which particle is most massive?
(a) #1 or #2
(a) L = 0.041 m
(b) L = 0.055 m
(c) L = 0.060 m
(d) L = 0.079 m
(e) L = 0.082 m
(a) into the page
(b) out of the page
(a) F = 1.06 × 10-13 N
(b) F = 1.59 × 10-13 N
(c) F = 2.22 × 10-13 N
(d) F = 2.98 × 10-13 N
(e) F = 3.78 × 10-13 N
Two fixed conductors are connected by a resistor of resistance 15
ohms. The two fixed conductors are separated by 3 m. A moving conductor
slides on them at velocity 7 m/s. Out of the page is a uniform magnetic
field (shown by the black dots in the figure) with a magnitude of
2x10-3T. Points a and b are two points on the
circuit just above and below the resistor.
In which direction does the current flow through the resistor?
(a) from a to b
(b) from b to a
(a) 0.39 × 10-5 N
(b) 1.7 × 10-5 N
(c) 5.3 × 10-5 N
(d) 12. × 10-5 N
(e) 53. × 10-5 N
(a) 0.118 × 10-3 W
(b) 0.842 × 10-3 W
(c) 3.27 × 10-3 W
(d) 38.7 × 10-3 W
(e) 73.2 × 10-3 W
(a) The power increases by a factor of 2.
(b) The power decreases by a factor of 2.
(c) The power increases by a factor of 4.
(d) The power decreases by a factor of 4.
(e) The power is unchanged.
In this problem all voltages and currents given and asked for are
rms values. The values of the frequency of the generator, the
capacitance, inductance, and impedance of the circuit are given to the
right of the circuit, along with the rms current flowing in the
What is the resistance R of this circuit?
(a) R = 125 W
(b) R = 197 W
(c) R = 307 W
(d) R = 428 W
(e) R = 632 W
(a) 11.6 V
(b) 24.5 V
(c) 49.2 V
(a) below the resonant frequency.
(b) above the resonant frequency.
(a) VC = 11.6 V
(b) VC = 24.5 V
(c) VC = 39.8 V
(d) VC = 49.2 V
(e) VC = 78.6 V
In the figure is shown a rectangular loop of wire shown in edge view.
The loop consists of a single turn of wire that is being rotated at a
constant frequency in a uniform, horizontal magnetic field as indicated
in the figure, where the sense of rotation is shown. Wires a and
b, which are perpendicular to the plane of the paper, are
indicated by arrows. The loop has a finite resistance, and has an
induced current flowing in it.
At the moment shown in the figure, the flux through the loop is
(a) out of the page in wire a, into the page in wire b.
(b) into the page in wire a, out of the page in wire b.
(a) larger than it is for the loop in the position shown.
(b) smaller than it is for the loop in the position shown.
(c) the same as it is for the loop in the position shown.
(a) horizontal direction.
(b) vertical direction.
In the figure is shown a square loop carrying a current of 2.5
A in a uniform B field of .02 T. The B-field makes an angle of 45°
with the sides of the loop. The length of a loop side is .03 m.
What is |Fab| the magnitude of the magnetic force on side
(a) |Fab| = 0 N
(b) |Fab| = 3.6 × 10-4 N
(c) |Fab| = 10.6 × 10-4 N
(d) |Fab| = 15.0 × 10-4 N
(e) |Fab| = 18.4 × 10-4 N
(a) out of the page.
(b) into the page.
(a) 0 Nm
(b) 3.18 × 10-5 Nm
(c) 4.50 × 10-5 Nm
The wires are located at (-2,0) meters and (2,0) meters. The former
carries 3 A coming out from the sheet of the paper, and the latter 3 A
going into it.
What is By, the y component of the magnetic field at the
(a) By = -6 × 10-7 T
(b) By = -3 × 10-7 T
(c) By = 0 T
(d) By = +3 × 10-7 T
(e) By = +6 × 10-7 T
(a) F = -2.25 × 10-6 N
(b) F = -1.25 × 10-6 N
(c) F = 0 N
(d) F = +1.25 × 10-6 N
(e) F = +2.25 × 10-6 N
A circular conducting loop with resistance of 5 ohms and diameter
d=0.4 m surrounds a long solenoid with radius R=0.15 m and
2x104 turns/meter. The current in the solenoid is flowing in
the counterclockwise direction producing a uniform magnetic field inside
the solenoid of B=0.75 T.
From the end view, the magnetic field at the center of the solenoid
(a) into the page.
(b) out of the page.
(a) Is = 9.5 A
(b) Is = 16.4 A
(c) Is = 29.8 A
(d) Is = 58.7 A
(e) Is = 68.2 A
Calculate IL the magnitude of the average induced current
in the outside loop while the current in the solenoid is being
(a) IL = 2.12 × 10-3 A
(b) IL = 2.46 × 10-3 A
(c) IL = 3.18 × 10-3 A
(d) IL = 3.76 × 10-3 A
(e) IL = 4.30 × 10-3 A